Given,
\(F=1\,N\)
\(\eta=0.02 \text { decapoise }=0.02\,N / sm ^2\)
\(A=20\,m ^2\)
The drag force is given by
\(F =\eta A \frac{ dv }{ dx }\)
\(\frac{ dv }{ dx }=\frac{ F }{\eta A }=\frac{1}{0.02 \times 20}\)
velocity gradient, \(\frac{ dv }{ dx }=2.5\,s ^{-1}\)
$( g =9.8\,m / s ^2$ આપેલું છે.)