\(\sqrt{2 gh }=\frac{2}{9} \frac{ r ^{2}( d -\rho) g }{\eta}\)
\(\sqrt{2 gh }=\frac{2}{9} \frac{10^{-8}(10000-1000) \times 10}{10^{-5}}\)
\(=\frac{2}{9} \times 10^{-8} \frac{9 \times 10^{4}}{10^{-5}}=20\)
\(2 \times 10 \times h =400\)
\(h =20 \,m\)
કોલમ - $\mathrm{I}$ | કોલમ - $\mathrm{II}$ |
$(a)$ વેલોસિટી હેડ | $(i)$ $\frac{P}{{\rho g}}$ |
$(b)$ પ્રેશર હેડ | $(ii)$ $h$ |
$(iii)$ $\frac{{{v^2}}}{{2g}}$ |