Two batteries, one of $emf$ $18\, volts$ and internal resistance $2\,\Omega $ and the other of $emf$ $12\, volt$ and internal resistance $1\,\Omega $, are connected as shown. The voltmeter $V$ will record a reading of .............. $\mathrm{volt}$
Medium
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$ \mathrm{E}_{\mathrm{net}} =\frac{\mathrm{E}_{1} \mathrm{r}_{2}+\mathrm{E}_{2} \mathrm{r}_{1}}{\mathrm{r}_{1}+\mathrm{r}_{2}} $
$=\frac{(18 \times 1)+(12 \times 2)}{(2+1)}$
$ \mathrm{E}_{\mathrm{net}} =\frac{18+24}{3}=\frac{42}{3}=14 \mathrm{\,volt} $
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