In parallel, ${I_2} = \frac{E}{{2 + \frac{r}{2}}} = \frac{{2E}}{{4 + r}}$
Since ${i_1} = {i_2}$ $ \Rightarrow $ $\frac{{2E}}{{4 + r}} = \frac{{2E}}{{2 + 2r}}$ $ \Rightarrow $ $r = 2\,\Omega $
Reason : Kirchoff 's loop rule follows from conservation of momentum.



