Two blocks $A$ and $B$ are released from the top of a rough inclined plane so that $A$ slides along the plane and $B$ falls down freely. Which will have higher velocity on reaching the ground ?
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As the block $A$ slides down along the rough inclined plane, it will lose energy due to opposing frictional force. Hence, the block $B$, which is falling freely, will reach the ground with higher velocity.
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(considering $4\ kg$ block doesn't fall on ground)
Consider the following statements
$(i)$ Time when relative motion between them is stopped is $1.4\ second$.
$(ii)$ Time when relative motion between them is stopped in $1.2\ second$
$(iii)$ The common velocity of the two blocks is $8\ m/s$, towards right.
$(iv)$ The displacement of the $4\, kg$ block when relative motion stopped is$10.8\ m$.
Which of the fstatements is/are correct
