A block of mass $M$ is sliding down the plane. Coefficient of static friction is $\mu _s$ and kinetic friction is $\mu _k.$ Then friction force acting on the block is :-
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$\mathrm{N}=(\mathrm{F}+\mathrm{Mg}) \cos \theta$
$\therefore$ Friction force $=\mu_{\mathrm{k}}(\mathrm{F}+\mathrm{mg}) \cos \theta$
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