Given that ${a_1}\sqrt {\frac{{{K_1}}}{m}} = {a_2}\sqrt {\frac{{{K_2}}}{m}} $
==> $\frac{{{a_1}}}{{{a_2}}} = \sqrt {\frac{{{K_2}}}{{{K_1}}}} $

${y_1} = 8\,\cos\, \omega t;\,{y_2} = 4\,\cos \,\left( {\omega t + \frac{\pi }{2}} \right)$ ;
${y_3} = 2\cos \,\left( {\omega t + \pi } \right);\,{y_4} = \,\cos \,\left( {\omega t + \frac{{3\pi }}{2}} \right)$ ,
are superposed on each other. The resulting amplitude and phase are respectively;
