Four simple harmonic vibrations:

${y_1} = 8\,\cos\, \omega t;\,{y_2} = 4\,\cos \,\left( {\omega t + \frac{\pi }{2}} \right)$ ; 

${y_3} = 2\cos \,\left( {\omega t + \pi } \right);\,{y_4} = \,\cos \,\left( {\omega t + \frac{{3\pi }}{2}} \right)$ , 

are superposed on each other. The resulting amplitude and phase are respectively;

Medium
Download our app for free and get startedPlay store
$\cos \theta=\hat{i}$

$\sin \theta=\hat{j}$

Result at $=8 \hat{j}-4 \hat{i}-2 \hat{j}+i$

$=-3 \hat{i}+6 j$

Magnitude $=\sqrt{45}$

$\tan \theta=\frac{1}{2}$

$\theta=\tan ^{-1}\left(\frac{1}{2}\right)$

art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    A particle execute $S.H.M.$ along a straight line. The amplitude of oscillation is $2 \,cm$. When displacement of particle from the mean position is $1 \,cm$, the magnitude of its acceleration is equal to magnitude of its velocity. The time period of oscillation is ........
    View Solution
  • 2
    The mass of a particle is $1\,\,kg$ and it is moving along  $x-$ axis. The period of its small oscillation is $\frac {\pi }{2}$ . Its potential energy may be
    View Solution
  • 3
    On a frictionless horizontal plane, a bob of mass $m=0.1 kg$ is attached to a spring with natural length $l_0=0.1 m$. The spring constant is $k_1=0.009 Nm ^{-1}$ when the length of the spring $I > l_0$ and is $k_2=0.016 Nm ^{-1}$ when $ I < l_0$. Initially the bob is released from $l=0.15 m$. Assume that Hooke's law remains valid throughout the motion. If the time period of the full oscillation is $T=(n \pi) s$, then the integer closest to $n$ is. . . . .
    View Solution
  • 4
    A particle of mass $m$ oscillates with simple harmonic motion between points ${x_1}$ and ${x_2}$, the equilibrium position being $O$. Its potential energy is plotted. It will be as given below in the graph
    View Solution
  • 5
    Maximum amplitude(in $cm$) of $SHM$ so block A will not slip on block $B , K =100 N / m$
    View Solution
  • 6
    A pendulum has time period $T$ in air. When it is made to oscillate in water, it acquired a time period $T' = \sqrt 2 T$. The density of the pendulum bob is equal to (density of water $= 1$)
    View Solution
  • 7
    Given below are two statements:

    Statement $I :$ A second's pendulum has a time period of $1$ second.

    Statement $II :$ It takes precisely one second to move between the two extreme positions.

    In the light of the above statements, choose the correct answer from the options given below:

    View Solution
  • 8
    The diagram shows two oscillations. What is the phase difference between the oscillations?
    View Solution
  • 9
    $Assertion :$ In simple harmonic motion, the velocity is maximum when the acceleration is minimum.
    $Reason :$ Displacement and velocity of $S.H.M.$ differ in phase by $\frac{\pi }{2}$
    View Solution
  • 10
    When a body of mass $1.0\, kg$ is suspended from a certain light spring hanging vertically, its length increases by $5\, cm$. By suspending $2.0\, kg$ block to the spring and if the block is pulled through $10\, cm$ and released the maximum velocity in it in $m/s$ is : (Acceleration due to gravity $ = 10\,m/{s^2})$
    View Solution