Two bulbs are in parallel and they together consume $48\, W$ from a battery of $6\, V$. The resistance of each bulb is ............ $\Omega$
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The bulbs are connected in parallel, hence each bulb consumes $\frac{{48}}{2} = 24\,W.$
Therefore $\frac{{{V^2}}}{R} = 24$
$ \Rightarrow $ $R = \frac{{6 \times 6}}{{24}} = 1.5\,\Omega $
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