Two bulbs, one of $200 \,W$ and the other of $100 \,W$ are connected in series with a $100 \,V$ battery which has no internal resistance. Then,
KVPY 2009, Medium
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(d)
Resistance of bulb is inversely proportional to its rated power.
$\Rightarrow R=\frac{V_{\text {rated }}^2}{P_{\text {rated }}} \Rightarrow R \propto \frac{1}{P_{\text {rated }}}$
As bulbs are in series, so same current flows through them at all instances. Power dissipation in a series combination is
$P=I^2 R \Rightarrow P \propto R$
$\text { or }P \propto \frac{1}{P_{\text {rated. }}}$
So, power dissipation is more in the $100 W$ bulb. This makes option (d) correct.
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