Two capacitances of capacity ${C_1}$ and ${C_2}$ are connected in series and potential difference $V$ is applied across it. Then the potential difference across ${C_1}$ will be
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(c) Charge flowing $ = \frac{{{C_1}{C_2}}}{{{C_1} + {C_2}}}\,V$. So potential difference across ${C_1} = \frac{{{C_1}{C_2}V}}{{{C_1} + {C_2}}} \times \frac{1}{{{C_1}}}$$ = \frac{{{C_2}V}}{{{C_1} + {C_2}}}$
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