Question
Two capacitors each having capacitance C and breakdown voltage V are joined in series. The capacitance and the breakdown voltage of the combination will be:
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$\text{2C}\ \text{and}\ \text{2V}$
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$\frac{\text{C}}{2}\ \text{and}\ \frac{\text{V}}{2}$
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$\text{2C}\ \text{and}\ \frac{\text{V}}{2}$
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$\frac{\text{C}}{2}\ \text{and}\ \text{2V}$

