Question
Two capacitors each having capacitance C and breakdown voltage V are joined in series. The capacitance and the breakdown voltage of the combination will be:

  1. $\text{2C}\ \text{and}\ \text{2V}$

  2. $\frac{\text{C}}{2}\ \text{and}\ \frac{\text{V}}{2}$

  3. $\text{2C}\ \text{and}\ \frac{\text{V}}{2}$

  4. $\frac{\text{C}}{2}\ \text{and}\ \text{2V}$

Answer

  1. $\frac{\text{C}}{2}\ \text{and}\ \text{2V}$

Explanation:

Since the voltage gets added up when the capacitors are connected in series, the voltage of the combination is 2V.

Also, the capacitance of a series combination is given by

$\frac{1}{\text{C}_{\text{net}}}=\frac{1}{\text{C}_1}+\frac{1}{\text{C}_2}$

Here,

C​net​ = Net capacitance of the combination

$\text{C}_1=\text{C}_2=\text{C}$

$\therefore\text{C}_{\text{net}}=\frac{\text{C}}{2}$

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