Force on a charged particle moving in region of magnetic field is
$F =q( v \times B )$
Clearly, $F$ is perpendicular to both $v$ and $B$.
As, magnetic force is perpendicular to velocity of moving charged particle. So, work done in time $\Delta t$ is
$W=( F \cdot v ) \Delta t=0$
$\text { Hence, } W_1=W_2=0$



Statement $(I)$: When an object is placed at the centre of curvature of a concave lens, image is formed at the centre of curvature of the lens on the other side.
Statement $(II)$: Concave lens always forms a virtual and erect image.
In the light of the above statements, choose the correct answer from the options given below:
