Two condensers, one of capacity $C$ and other of capacity $C/2$ are connected to a $V-$ volt battery, as shown in the figure. The work done in charging fully both the condensers is
AIPMT 2007, Medium
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As the capacitors are connected in parallel, therefore potential difference across both the condensors remains the same.

$\therefore Q_{1}=C V ;$

$Q_{2} =\frac{C}{2} V $

$\text { Also }, Q =Q_{1}+Q_{2}$

$ = CV+\frac{C}{2} V=\frac{3}{2} C V$

Work done in charging fully both the condensors is given by

$W=\frac{1}{2} Q V=\frac{1}{2} \times\left(\frac{3}{2}\, C V\right) V=\frac{3}{4} \,C V^{2}$

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