MCQ
Two elements $X$ and $Y$ have atomic weights of $14$ and $16$. They form a series of compounds $A, B, C, D$ and $E$ in which the same amount of element $X$, $Y $ is present in the ratio $1 : 2 : 3 : 4 : 5$. If the compound $A$ has $28$ parts by weight of $X $ and $16$ parts by weight of $Y$, then the compound of $C$ will have $28$ parts weight of $X$ and
- A$32$ parts by weight of $Y$
- ✓$48$ parts by weight of $Y$
- C$64$ parts by weight of $Y$
- D$80$ parts by weight of $Y$