a
$\Delta x=\frac{\lambda}{2}$ $\Delta \mathrm{x}$ path difference
$\Delta \phi=\mathrm{k} \Delta \mathrm{x}$
$=\frac{2 \pi}{\lambda} \times \frac{\lambda}{2}=\pi$
Hence destructive interference will occur at point $P.$
$A_{\text {resultant }}=\sqrt{(2 a)^{2}+a^{2}-4 a^{2}}=a$
It will remain constant with time.