MCQ
Two identical pendulum $A$ and $B$ are suspended from the same point. The bobs are given positive charges, with $A$ having more charge than $B$ . They diverge and reach at equilibrium, with $A$ and $B$ making angles $\theta _1$ and $\theta _2$ with the vertical respectively, Then
  • $\theta _1 = \theta _2$
  • B
    $\theta _1 > \theta _2$
  • C
    $\theta _1 < \theta _2$
  • D
    Tension in $A$ is smaller than in $B$

Answer

Correct option: A.
$\theta _1 = \theta _2$
a
According the conditions of coulomb forces, both the balls repel each other with a force

$\mathrm{F}_{\mathrm{e}}=\frac{\mathrm{q}_{1} \mathrm{q}_{2}}{4 \pi \varepsilon_{0} \mathrm{r}}$

Thus, forces $\mathrm{F}_{\mathrm{e}}$ and $\mathrm{mg}$ are identical on both the balls, hence in static equilibrium

$\theta_{1}=\theta_{2}.$

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