$\Delta W_{1}=\Delta W_{2}$ $\Rightarrow \Delta Q_{1}-\Delta U_{1}=\Delta Q_{2}-\Delta U_{2}$

$\Rightarrow \Delta Q_{1}-\Delta Q_{2}=\Delta U_{1}-\Delta U_{2}$

So, option $a$ is correct.

Process is isobaric

Hence $\Delta Q_{1}=n C_{p 1} \Delta T_{1}=\frac{5}{2} n R \Delta T_{1}=\frac{5}{2} P_{0} V_{0}$

Also $\Delta Q_{2}=n C_{P 2} \Delta T_{2}=\frac{7}{2} n R \Delta T_{2}=\frac{7}{2} P_{0} V_{0}$

Hence $\Delta Q_{2}>\Delta Q_{1}$

$\Rightarrow \Delta U_{1}+\Delta W_{1}>\Delta U_{2}+\Delta W_{2}$

So, option $b$ is correct

$\Delta U_{1}=n C_{v 1} \Delta T_{1}=\frac{3}{2} n R \Delta T_{1}=\frac{3}{2} P_{0} V_{0}$

$\Delta U_{2}=n C_{v 2} \Delta T_{2}=\frac{5}{2} n R \Delta T_{2}=\frac{5}{2} P_{0} V_{0}$

Hence $\Delta U_{2}>\Delta U_{1}$

So, option $c$ is also correct