MCQ
Two parallel discs are connected by a rigid rod of length $L=0.5 \,m$ centrally. Each disc has a slit oppositely placed as shown in the figure. A beam of neutral atoms are incident on one of the discs axially at different velocities $v$, while the system is rotated at angular speed of $600 \,rev / second$, so that atoms only with a specific velocity emerge at the other end. Calculate the two largest speeds (in metre/second) of the atoms that will emerge at the other end.
  • A
    $75,25$
  • B
    $100,50$
  • C
    $300,100$
  • $600,200$

Answer

Correct option: D.
$600,200$
d
(d)

Time at which discs gaps are alined,

$t=\frac{\pi}{\omega}, \frac{3 \pi}{\omega}, \frac{5 \pi}{\omega}, \ldots$

So, speeds of atoms that emerges on other side are

$v_1=\frac{0.5}{\frac{\pi}{600} \times 2 \pi}=600 \,ms ^{-1}$

$\text { and } v_2=\frac{0.5}{\frac{3 \pi}{600} \times 2 \pi}=200 \,ms ^{-1}$

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