MCQ
Two particles are executing S.H.M. The equation of their motion are ${y_1} = 10\sin \left( {\omega \,t + \frac{{\pi T}}{4}} \right),$ ${y_2} = 25\sin \,\left( {\omega \,t + \frac{{\sqrt 3 \pi T}}{4}} \right)$. What is the ratio of their amplitude
  • A
    $1:1$
  • $2:5$
  • C
    $1:2$
  • D
    None of these

Answer

Correct option: B.
$2:5$
b
(b) $\frac{{{a_1}}}{{{a_2}}} = \frac{{10}}{{25}} = \frac{2}{5}$

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