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STD 12 - 1. Electric charges and fields — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - 1. Electric charges and fields4 Marks
MCQ
Two protons $A$ and $B$ are placed in space between plates of a parallel plate capacitor charged upto $V$ volts (See fig.) Forces on protons are ${F_A}$ and ${F_B}$, then
  • A
    ${F_A} > {F_B}$
  • B
    ${F_A} < {F_B}$
  • ✓
    ${F_A} = {F_B}$
  • D
    Nothing can be said
✓

Answer

Correct option: C.
${F_A} = {F_B}$
c
(c) ${F_A} = {F_B}$; because an uniform electric field produced between the plates.

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