Two resistances {R_1} and {R_2} are made of different materials. The temperature coefficient of the material of {R

Q: Two resistances ${R_1}$ and ${R_2}$ are made of different materials. The temperature coefficient of the material of ${R_1}$ is $\alpha $ and of the material of ${R_2}$ is $ - \beta $. The resistance of the series combination of ${R_1}$ and ${R_2}$ will not change with temperature, if ${R_1}/{R_2}$ equals

d (d) ${R_1} + {R_2} = {R_1}(1 + \alpha t) + {R_2}(1 - \beta \,t)$ $==>$ ${R_1} + {R_2} = {R_1} + {R_2} + {R_1}\alpha t - {R_2}\beta t$ $==>$ $\frac{{{R_1}}}{{{R_2}}} = \frac{\beta }{\alpha }$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Two resistances ${R_1}$ and ${R_2}$ are made of different materials. The temperature coefficient of the material of ${R_1}$ is $\alpha $ and of the material of ${R_2}$ is $ - \beta $. The resistance of the series combination of ${R_1}$ and ${R_2}$ will not change with temperature, if ${R_1}/{R_2}$ equals

A$\frac{\alpha }{\beta }$
B$\frac{{\alpha + \beta }}{{\alpha - \beta }}$
C$\frac{{{\alpha ^2} + {\beta ^2}}}{{\alpha \beta }}$
D$\frac{\beta }{\alpha }$

Diffcult

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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