
$V_A=\frac{k q}{r}+\frac{k(-q)}{d-r}$
$V_B=\frac{-k q}{r}+\frac{k q}{d-r}$
$V=V_A-V_B=\frac{2 k q}{r}-\frac{2 k q}{d-r}=\frac{2 q}{4 \pi \varepsilon_0}\left[\frac{1}{r}-\frac{1}{d-r}\right]$
$V=\frac{q}{2 \pi \varepsilon_0}\left[\frac{d-2 r}{(r)(d-r)}\right]$
$d \gg r$
$V=\frac{q}{2 \pi \varepsilon_0}$
$\frac{q}{V}=2 \pi \varepsilon_0 r=C$



