If the capacitance of each capacitor in the tetrahedron shown is $C$ , then effective capacitance of the network across any two junctions is ......$C$
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One capacitor will be removed due to symmetry if we calculated then one of the capacitor will be removed and the remaining circuit will be
$\mathrm{Ceq}=\mathrm{C}+\frac{\mathrm{C}}{2}+\frac{\mathrm{C}}{2}=2 \mathrm{\,C}$
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