Question

Answer

i. Let $E_1$ and $E_2$ denotes the events that Ankit and Vinod will respectively qualify the exam.
$\begin{array}{l}P\left(E_1 \cup E_2\right)= P \left( E _1\right)+ P \left( E _2\right)- P \left( E _1 \cap E _2\right) \\ =0.05+0.10-0.02=0.13\end{array}$
iii. Let $E_1$ and $E_2$ denotes the events that Ankit and Vinod will respectively qualify the exam.
$\begin{array}{l}=P\left(E_1^{\prime} \cap E_2^{\prime}\right)=P\left(\left(E_1 \cup E_2\right)^{\prime}\right) \\ =1- P \left(E_1 \cup E_2\right)=1-0.13=0.87\end{array}$
OR
Let $E_1$ and $E_2$ denotes the events that Ankit and Vinod will respectively qualify the exam.
The probability that Vinod will not qualify the exam. 
Probability that only one of them will qualify the exam $= P \left(\left( E _1- E _2\right) \cup\left( E _2- E _1\right)\right)$
$\begin{array}{l}=P\left(E_1-E_2\right)+P\left(E_2-E_1\right) \\ =P\left(E_1 \cup E_2\right)-P\left(E_1 \cap E_2\right) \\ =0.13-0.02=0.11\end{array}$

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⇒ a = c and b = d

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6, 8

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(A . B) = (B . A)

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Image

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This is shown in the figure
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Based on above information, answer the following questions.

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