Two vessels $A$ and $B$ have the same base area and contain water to the same height, but the mass of water in $A$ is four times that in $B$. The ratio of the liquid thrust at the base of $A$ to that at the base of $B$ is
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The thrust due to any liquid at the bottom of the vessel is only a function of its base area.
since, in the given figure, both the vessels have the same base area therefore, they will have an equal thrust due to liquid.
Hence, the ratio of the thrusts is equal to $1: 1$
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