Two wires $A$ and $B$ are of same materials. Their lengths are in the ratio $1 : 2$ and diameters are in the ratio $2 : 1$ when stretched by force ${F_A}$ and ${F_B}$ respectively they get equal increase in their lengths. Then the ratio ${F_A}/{F_B}$ should be
A$1:2$
B$1:1$
C$2:1$
D$8:1$
Medium
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D$8:1$
d (d) $F = Y \times A \times \frac{l}{L}$$⇒$ $F \propto \frac{{{r^2}}}{L}$ $(Y$ and $l$ are constant$)$
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