Under a pressure head the rate of orderly volume flow of a liquid through a capillary tube is $Q$ . If the length of capillary tube is doubled and the diameter of tube is halved, the rate of flow would become
A$\frac {Q}{32}$
B$\frac {Q}{8}$
C$\frac {Q}{4}$
D$8Q$
Medium
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A$\frac {Q}{32}$
a $\mathrm{Q}=\frac{\pi \mathrm{Pr}^{4}}{8 \mathrm{n} \ell}$
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