Question
Under what condition, an ideal Carnot engine has 100% efficiency?

Answer

Efficiency of a Carnot engine is given by $\eta=\Big(1-\frac{\text{T}_2}{\text{T}_1}\Big)$ Where, $T_2$ = temperature of sink and $T_1$ = temperature of sink source. So, for $\eta=1$ or 100%, $T_2$ = 0K or heat is rejected in to a sink at 0K temperature.

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