c
(c)Let \({P_1} = P\), \({P_2} = {P_1} + 50\% \) of \({P_1}\)= \({P_1} + \frac{{{P_1}}}{2} = \frac{{3{P_1}}}{2}\)

\(E \propto {P^2}\)

==> \(\frac{{{E_2}}}{{{E_1}}} = {\left( {\frac{{{P_2}}}{{{P_1}}}} \right)^2} = {\left( {\frac{{3{P_1}/2}}{{{P_1}}}} \right)^2} = \frac{9}{4}\)

==>\({E_2} = 2.25E = {E_1} + 1.25{E_1}\)

\({E_2} = {E_1} + 125\% \;{\rm{of }}{E_1}\)

i.e. kinetic energy will increase by \(125\%.\)