Vessel $A$ is filled with hydrogen while vessel $B,$ whose volume is twice that of $A,$ is filled with the same mass of oxygen at the same temperature. The ratio of the mean kinetic energies of hydrogen and oxygen is
A$16:1$
B$1:8$
C$8:1$
D$1:1$
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D$1:1$
d Mean Kinetic energy, $K E_ m=\frac{f}{2} K_{B} T$
So, $\frac{K E_{m} \text { for } H_{2}}{K E_{m} \text { for } O_{2}}=\frac{\frac{B}{2} K_{B} T}{\frac{5}{2} K_{B} T}$$=\frac{1}{1}$
So, $1: 1$
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