MCQ
વિધેય $3\sin x - 4{\sin ^3}x $ એ . . . . મહતમ અંતરાલ માટે વધતું બને છે .
- ✓${\pi \over 3}$
- B${\pi \over 2}$
- C${{3\pi } \over 2}$
- D$\pi $
It is increasing, when $ - \pi /2 \le 3x \le \pi /2$
$i.e.,$ $ - \pi /6 \le x \le \pi /6$.
$\therefore$ The length of interval $= \left| {\,\frac{\pi }{6} - \left( { - \frac{\pi }{6}} \right)\,} \right|\, = \,\frac{\pi }{3}$.
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