MCQ
વિધેય $f(x) = {x^3} - 3{x^2} - 24x + 5$ એ . . .. અંતરાલમાં વધતું છે.
- ✓$( - \infty ,\, - 2) \cup (4,\infty )$
- B$( - 2,\infty )$
- C(-2, 4)
- D$( - \infty ,\,4)$
For increasing, $f'(x) > 0$ ==> $3{x^2} - 6x - 24 > 0$
==> ${x^2} - 2x - 8 > 0$
${x^2} - 4x + 2x - 8 > 0$ ==> $(x + 2)(x - 4) > 0$
$x \in ( - \infty ,\, - 2) \cup (4,\infty )$.
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