\(Be\upsilon = eE\)
or \(\quad v=\frac{E}{B}\) ...... \((i)\)
If \(V\) is the potential difference between the anode and the cathode, then
\({\frac{1}{2} m v^{2}=e V}\)
\({\frac{e}{m}=\frac{v^{2}}{2 V}}\) ..... \((ii)\)
Substituting the value of \(v\) from equation \((i)\) in equation \((ii)\), we get
\(\frac{e}{m}=\frac{E^{2}}{2 V B^{2}}\)
Specific charge of the cathode rays \(\frac{e}{m}=\frac{E^{2}}{2 V B^{2}}\)