MCQ
વિકલ સમીકરણ $\frac{{dy}}{{dx}} + y = \cos x$ નો ઉકેલ મેળવો.
- ✓$y = \frac{1}{2}(\cos x + \sin x) + c{e^{ - x}}$
- B$y = \frac{1}{2}(\cos x - \sin x) + c{e^{ - x}}$
- C$y = \cos x + \sin x + c{e^{ - x}}$
- Dએકપણ નહી.
So, $I.F.$ $ = {e^{\int_{}^{} {1dx} }} = {e^x}$
Hence solution is $y.{e^x} = \int_{}^{} {\cos x.{e^x}dx + c} $
==> $y = \frac{1}{2}(\cos x + \sin x) + c{e^{ - x}}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.