MCQ
વિકલ સમીકરણ $\frac{{dy}}{{dx}} + y{\sec ^2}x = \tan x{\sec ^2}x$ નો ઉકેલ મેળવો.
- ✓$y = \tan x - 1 + c{e^{ - \tan x}}$
- B${y^2} = \tan x - 1 + c{e^{\tan x}}$
- C$y{e^{\tan x}} = \tan x - 1 + c$
- D$y{e^{ - \tan x}} = \tan x - 1 + c$
Solution is $y{e^{\tan x}} = c + \int {\tan x{e^{\tan x}}{{\sec }^2}x\,dx} $
==> $y = c{e^{ - \tan x}} + \tan x - 1$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.