total mass of solution $=1460 \,g$
mass of $HCl =\frac{35}{100} \times 1460$
moles of $HCl =\frac{35 \times 1460}{100 \times 36.5}$
So molarity $=\frac{35 \times 1460}{100 \times 36.5}=14 \,M$
$( N _{ A }=6.02 \times 10^{23} \,mol ^{-1})$(નજીકનો પૂર્ણાંક)