Water from a tap emerges vertically downwards with an initial speed of $1.0\,ms^{-1}.$ The cross-sectional area of the tap is $10^{-4}\,m^2.$ Assume that the pressure is constant throughout the stream of water and that flow is streamlined. The cross-sectional area of the stream, $0.15\,m$ below the tap would be: (take $g = 10\,ms^{-2}$ )
  • A$5\times 10^{-4}\,m^2$
  • B$5\times 10^{-5}\,m^2$
  • C$1\times 10^{-5}\,m^2$
  • D$2\times 10^{-5}\,m^2$
JEE MAIN 2019, Medium
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