Water is flowing through a tube of non-uniform cross-section. Ratio of the radius at entry and exit end of the pipe is $3$ : $2$. Then the ratio of velocities at entry and exit of liquid is
Medium
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If velocities of water at entry and exit points are $\mathrm{v}_{1}$ and $\mathrm{v}_{2},$ then according to equation of continuity,
$A_{1} v_{1}=A_{2} v_{2} \Rightarrow \frac{v_{1}}{v_{2}}=\frac{A_{2}}{A_{1}}=\left(\frac{r_{2}}{r_{1}}\right)^{2}=\left(\frac{2}{3}\right)^{2}=\frac{4}{9}$
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