What amount of bromine will be required to convert $2g$ of phenol into $2, 4, 6−$tribromophenol?
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Write equation for chemical change, find molecular masses of reactants and products and solve it.Molecular weight of phenol
$= 12 \times 6 + 1 \times 6 + 16 = 94$
Molecular$ wt.$ of $Br_{2 }= 3 \times 160 = 480$
$\because 94$ of phenol requires $=480g$ of $Br_2$
$\therefore 2g$ of phenol requires = $\frac{480}{94}\times 2=10.22\text{g}$
The correct answer is $10.22g$
$= 12 \times 6 + 1 \times 6 + 16 = 94$
Molecular$ wt.$ of $Br_{2 }= 3 \times 160 = 480$
$\because 94$ of phenol requires $=480g$ of $Br_2$
$\therefore 2g$ of phenol requires = $\frac{480}{94}\times 2=10.22\text{g}$
The correct answer is $10.22g$
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