What is the correct order of reactivity of alcohols in the following reaction?
$\text{R}-\text{OH}+\text{HCL}\xrightarrow{\text{ZnCl}_2}\text{R}-\text{Cl}+\text{H}_2\text{O}$
$\text{R}-\text{OH}+\text{HCL}\xrightarrow{\text{ZnCl}_2}\text{R}-\text{Cl}+\text{H}_2\text{O}$
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- 3° > 2° > 1°
This reaction is a type of nucleophilic substitution reaction in which -OH group is replaced by -Cl. The intermediate formed by tertiary alcohol is more stable as carbocation is more stable than primary and secondary carbocation. Thus, the order of reactivity of alcohol will be 3° > 2° > 1°.
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