Question
What is the equivalent resistance between A and B in the given circuit (Fig?)
✓
Answer
Between A and B, the series combination of two resistors of resistances 2 ohm each is connected in parallel with the 1 ohm resistor.
Equivalent series resistance between A and B, R, = $=2+2=4 \Omega$
Now, between A and B this $4 \Omega$resistor is connected in parallel with $1 \Omega$ resistor.
Equivalent resistance between A and B, R = $\left(\frac{1}{4}+\frac{1}{1}\right)^{-1}=\left(\frac{5}{4}\right)^{-1}=\frac{4}{5} \Omega$
Equivalent series resistance between A and B, R, = $=2+2=4 \Omega$
Now, between A and B this $4 \Omega$resistor is connected in parallel with $1 \Omega$ resistor.
Equivalent resistance between A and B, R = $\left(\frac{1}{4}+\frac{1}{1}\right)^{-1}=\left(\frac{5}{4}\right)^{-1}=\frac{4}{5} \Omega$
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