Question
What is the length of a simple pendulum, which ticks seconds ?

Answer

From Eq. (13.26), the time period of a simple pendulum is given by,
$
T=2 \pi \sqrt{\frac{L}{g}}
$

From this relation one gets,
$
L=\frac{g T^2}{4 \pi^2}
$

The time period of a simple pendulum, which ticks seconds, is $2 s$. Therefore, for $g=9.8 m s ^{-2}$
$
\text { and } \begin{aligned}
T & =2 s , L \text { is } \\
& =\frac{9.8\left( m s ^{-2}\right) \times 4\left( s ^2\right)}{4 \pi^2} \\
& =1 m
\end{aligned}
$

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