What is the maximum acceleration of the particle doing the SHM y = 2sin left[ {frac{{pi t}}{2} + phi } right] where 2 is in

Q: What is the maximum acceleration of the particle doing the $SHM$ $y = 2\sin \left[ {\frac{{\pi t}}{2} + \phi } \right]$ where $2$ is in $cm$

b (b) Comparing given equation with standard equation, $y = a\sin (\omega t + \phi ),$ we get, $a = 2\,cm,$ $\omega = \frac{\pi }{2}$ $\therefore {A_{max}} = {\omega ^2}A$ $= {\left( {\frac{\pi }{2}} \right)^2} \times 2$ $ = \frac{{{\pi ^2}}}{2}\,cm/{s^2}$.

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

What is the maximum acceleration of the particle doing the $SHM$ $y = 2\sin \left[ {\frac{{\pi t}}{2} + \phi } \right]$ where $2$ is in $cm$

A$\frac{\pi }{2}\,cm/{s^2}$
B$\frac{{{\pi ^2}}}{2}\,cm/{s^2}$
C$\frac{\pi }{4}\,cm/{s^2}$
D$\frac{\pi }{4}\,cm/{s^2}$

Easy

STD 11 Science
NEET
STD 11 - 13. oscillations
Physics

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