All resistances in figure are $1\,\Omega$ each. The value of current ' $I$ ' is $\frac{a}{5}\,A$. The value of $a$ is
JEE MAIN 2022, Diffcult
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$R_{e q}=\frac{15 R}{8}=\frac{15}{8}\,\Omega$
$I=\frac{3}{\frac{15}{8}}=\frac{8}{5}\,A$
$\therefore a=8$
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