What is the position of image when an object is placed at a distance of 10cm from a convex lens of focal length 10cm?
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U = -10cm, f = 10cm We have,$\frac{1}{\text{v}}-\frac{1}{\text{u}}=\frac{1}{\text{f}}$
$\frac{1}{\text{v}}-\frac{1}{-10}=\frac{1}{10}$
$\frac{1}{\text{v}}=0$
$\text{v}=\frac{1}{0}=\infty$
At infinity.
$\frac{1}{\text{v}}-\frac{1}{-10}=\frac{1}{10}$
$\frac{1}{\text{v}}=0$
$\text{v}=\frac{1}{0}=\infty$
At infinity.
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