MCQ
What should be the equivalent weight of phosphorous acid, if $P=31; O=16; H=1$
  • A
    $82$
  • $41$
  • C
    $20.5$
  • D
    None of these

Answer

Correct option: B.
$41$
b
(b) The acid is dibasic.

Molecular weight of ${H_3}P{O_3}$$ = 3 + 31 + 48 = 82$

$\therefore $ Equivalent weight $ = \frac{{{\rm{Molecular weight}}}}{{{\rm{Basicity}}}} = \frac{{82}}{2}= 41.$

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