What will happen when a 40, watt, 220, volt lamp and 100, watt, 220, volt lamp are connected in series across 40, volt supply

Q: What will happen when a $40\, watt$, $220\, volt$ lamp and $100\, watt$, $220\, volt$ lamp are connected in series across $40\, volt$ supply

d (d) Bulb $(I)$ : Rated current ${I_1} = \frac{P}{V} = \frac{{40}}{{220}} = \frac{2}{{11}}\,amp.$ Resistance ${R_1} = \frac{{{V^2}}}{P} = \frac{{{{(220)}^2}}}{{40}} = 1210\,\Omega $ Bulb $(II)$ : Rated current ${I_2} = \frac{{100}}{{220}} = \frac{5}{{11}}\,amp$ Resistance ${R_2} = \frac{{{{(220)}^2}}}{{100}} = 484\,\Omega $ When both are connected in series across $40\, V$ supply Total current through supply $I = \frac{{40}}{{{P_1} + {P_2}}} = \frac{{40}}{{1210 + 484}} = \frac{{40}}{{1254}} = 0.03\,A$ This current is less than the rated current of each bulb. So neither bulb will fuse. Short Trick : Since $V_{Applied}$ $<$ $V_{Rated}$, neither bulb will fuse.

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

What will happen when a $40\, watt$, $220\, volt$ lamp and $100\, watt$, $220\, volt$ lamp are connected in series across $40\, volt$ supply

A$100\, watt$ lamp will fuse
B$40\, watt$ lamp will fuse
C
Both lamps will fuse
D
Neither lamp will fuse

Diffcult

STD 11 Science
JEE
STD 12 - 3. current electricity
Physics

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