What would be the molality of 20 % (mass/mass) aqueous solution o… - Vidyadip

MCQ

What would be the molality of $20\%$ (mass/mass) aqueous solution of $KI$ ? (molar mass of $KI = 166\, g\, mol^{-1}$)

A
$1.08$
B
$1.48$
✓
$1.51$
D
$1.35$

✓

Answer

Correct option: C.

$1.51$

c
$20\%\,w/w\,KI$

Mass of solute $(KI) = 20\,g$

Mass of solvent $= 100-20 = 80\,g$

Molar mass of $KI = 38+128 = 166$

Molality $ = \frac{{gm\,(solute)}}{{mw\, \times Kg\,(solvent)}} = \frac{{20 \times 1000}}{{166 \times 80}} = 1.506 = 1.51$

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