When a mass $M$ is attached to the spring of force constant $k$, then the spring stretches by $l$. If the mass oscillates with amplitude $l$, what will be maximum potential energy stored in the spring
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(c) $Mg = Kl$
==> ${U_{\max }} = \frac{1}{2}K{l^2} = \frac{1}{2}mgl$
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